Re: [PATCH v7 08/18] can: rcar_canfd: Simplify RCANFD_GAFLCFG_SETRNC macro

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Hi Vincent,

On Fri, 28 Mar 2025 at 11:39, Vincent Mailhol
<mailhol.vincent@xxxxxxxxxx> wrote:
> On 26/03/2025 at 21:19, Biju Das wrote:
> > The shift values in RCANFD_GAFLCFG_SETRNC are dictated by the field width:
> >   - R-Car Gen4 packs 2 values in a 32-bit word, using a field width
> >     of 16 bits,
> >   - R-Car Gen3 packs up to 4 values in a 32-bit word, using a field
> >     width of 8 bits.
> >
> > Add rnc_field_width variable to struct rcar_canfd_hw_info to handle this
> > difference and simplify the shift value in RCANFD_GAFLCFG_SETRNC macro by
> > using a formula (32 - (n % rnc_stride + 1) * rnc_field_width).
> >
> > Reviewed-by: Geert Uytterhoeven <geert+renesas@xxxxxxxxx>
> > Signed-off-by: Biju Das <biju.das.jz@xxxxxxxxxxxxxx>

> > --- a/drivers/net/can/rcar/rcar_canfd.c
> > +++ b/drivers/net/can/rcar/rcar_canfd.c
> > @@ -89,7 +89,7 @@
> >  /* RSCFDnCFDGAFLCFG0 / RSCFDnGAFLCFG0 */
> >  #define RCANFD_GAFLCFG_SETRNC(gpriv, n, x) \
> >       (((x) & ((gpriv)->info->num_supported_rules - 1)) << \
> > -      (reg_gen4(gpriv, 16, 24) - ((n) & 1) * reg_gen4(gpriv, 16, 8)))
> > +      (32 - (((n) % (gpriv)->info->rnc_stride + 1) * (gpriv)->info->rnc_field_width)))
>
> I can not follow how this is the same. Let's take the gen4 as an
> example. Before:
>
>   (reg_gen4(gpriv, 16, 24) - ((n) & 1) * reg_gen4(gpriv, 16, 8))) =
>   16 - ((n & 1) * 16)
>
> So, I have:
>
>          n      shift value
>         ---------------------------------
>          0      16 - ((0 & 1) * 16) = 0

16

>          1      16 - ((1 & 1) * 16) = 16

0

>          2      16 - ((2 & 1) * 16) = 0

16

>          3      16 - ((3 & 1) * 16) = 16

0

>          4      16 - ((4 & 1) * 16) = 0

16

>
> After:
>
>   (32 - ((n % rnc_stride + 1)) * rnc_field_width) =
>   32 - ((n % (2 + 1)) * 16) =

You got the operator precedence wrong: should be (n % 2) + 1 instead
of n % (2 + 1).

>   32 - ((n % 3) * 16)
>
>          n      shift value
>         ---------------------------------
>          0      32 - ((0 % 3) * 16) = 32
>          1      32 - ((1 % 3) * 16) = 16
>          2      32 - ((2 % 3) * 16) = 0
>          3      32 - ((3 % 3) * 16) = 32
>          4      32 - ((4 % 3) * 16) = 16
>
> Is there something wrong in my calculation? What am I missing?
>
> More generally, it is really hard to review and understand what this
> macro does.

It prepares a value for storing in a 16-bit or 8-bit field of a 32-bit
register, where the fields are numbered MSB-first.

Gr{oetje,eeting}s,

                        Geert

-- 
Geert Uytterhoeven -- There's lots of Linux beyond ia32 -- geert@xxxxxxxxxxxxxx

In personal conversations with technical people, I call myself a hacker. But
when I'm talking to journalists I just say "programmer" or something like that.
                                -- Linus Torvalds




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