Re: script to loop through dates

[olivares33561 via users <users@xxxxxxxxxxxxxxxxxxxxxxx>]

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On Friday, June 27th, 2025 at 7:43 AM, olivares33561 via users <users@xxxxxxxxxxxxxxxxxxxxxxx> wrote:

> 
> 
> 
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> Sent from ProtonMail, encrypted email based in Switzerland.
> 
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> On Friday, June 27th, 2025 at 7:18 AM, olivares33561 via users users@xxxxxxxxxxxxxxxxxxxxxxx wrote:
> 
> > Sent from ProtonMail, encrypted email based in Switzerland.
> > 
> > Sent with Proton Mail secure email.
> > 
> > On Friday, June 27th, 2025 at 7:02 AM, Will McDonald wmcdonald@xxxxxxxxx wrote:
> > 
> > > On Fri, 27 Jun 2025 at 12:32, olivares33561 via users users@xxxxxxxxxxxxxxxxxxxxxxx wrote:
> > > 
> > > > I am struggling to create a script that generates a series of dates with special "+%Y.%m.%d" like the following
> > > > 
> > > > 2025.06.01
> > > > 2025.06.01
> > > > 2025.06.01
> > > > 
> > > > I found several examples but can't succeed to get what I want
> > > > ------
> > > > 
> > > > #!/bin/bash
> > > > start=$1
> > > > end=$2
> > > > 
> > > > start=$(date -d $start +%Y%m%d)
> > > > end=$(date -d $end +%Y%m%d)
> > > > 
> > > > while [[ $start -le $end ]]
> > > > do
> > > > echo $start
> > > > start=$(date -d"$start + 1 day" +"%Y%m%d")
> > > > done
> > > > ------
> > > 
> > > The date command can't parse dates with periods/dots in this step: start=$(date -d $start +%Y%m%d)
> > > 
> > > Example:
> > > 
> > > wmcdonald@DESKTOP-9HGJE25:~$ echo $IN
> > > 2025.07.01
> > > wmcdonald@DESKTOP-9HGJE25:~$ date -d $IN +%Y%m%d
> > > date: invalid date ‘2025.07.01’
> > > wmcdonald@DESKTOP-9HGJE25:~$
> > > 
> > > So that step's going to fail. And the while loop can't evaluate the dotted notation strings for greater/less than. The easiest thing to do is strip the dots from the input, then add them back in in the output. This isn't elegant, and someone may provide a better answer but this works:
> > > 
> > > #!/bin/bash
> > > start=$1
> > > end=$2
> > > 
> > > start=$(date -d $(echo $start | sed 's/\./-/g') +%Y%m%d)
> > > end=$(date -d $(echo $end | sed 's/\./-/g') +%Y%m%d)
> > > 
> > > date -d"$start" +%Y.%m.%d
> > > 
> > > while [[ $start -lt $end ]]
> > > do
> > > date -d"$start + 1 day" +%Y.%m.%d
> > > start=$(date -d"$start + 1 day" +%Y%m%d)
> > > done
> > > 
> > > wmcdonald@DESKTOP-9HGJE25:~$ ./daterange.sh 2025.07.01 2025.07.16
> > > 2025.07.01
> > > 2025.07.02
> > > 2025.07.03
> > > 2025.07.04
> > > 2025.07.05
> > > 2025.07.06
> > > 2025.07.07
> > > 2025.07.08
> > > 2025.07.09
> > > 2025.07.10
> > > 2025.07.11
> > > 2025.07.12
> > > 2025.07.13
> > > 2025.07.14
> 
> 
> Dear Will, thanks for your help. I was able to do it.
> The following does the job!
> ------
> #!/bin/bash
> start=$1
> end=$2
> 
> start=$(date -d $(echo $start | sed 's/\./-/g') +%Y%m%d)
> end=$(date -d $(echo $end | sed 's/\./-/g') +%Y%m%d)
> 
> date -d"$start" +%Y.%m.%d
> 
> while [[ $start -lt $end ]]
> do
> for i in {1..4}; do
> date -d"$start + 1 day" +%Y.%m.%d
> done
> start=$(date -d"$start + 1 day" +%Y%m%d)
> done
> ------
> 
> 
> Regards,
> 
> 
> Antonio
> 
> --

It does not print start day four times.  Almost there.  

Best Regards,


Antonio 

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