Sent from ProtonMail, encrypted email based in Switzerland. Sent with Proton Mail secure email. On Friday, June 27th, 2025 at 7:02 AM, Will McDonald <wmcdonald@xxxxxxxxx> wrote: > On Fri, 27 Jun 2025 at 12:32, olivares33561 via users <users@xxxxxxxxxxxxxxxxxxxxxxx> wrote: > > > I am struggling to create a script that generates a series of dates with special "+%Y.%m.%d" like the following > > > > 2025.06.01 > > 2025.06.01 > > 2025.06.01 > > > > I found several examples but can't succeed to get what I want > > ------ > > > > #!/bin/bash > > start=$1 > > end=$2 > > > > start=$(date -d $start +%Y%m%d) > > end=$(date -d $end +%Y%m%d) > > > > while [[ $start -le $end ]] > > do > > echo $start > > start=$(date -d"$start + 1 day" +"%Y%m%d") > > done > > ------ > > > The date command can't parse dates with periods/dots in this step: start=$(date -d $start +%Y%m%d) > > Example: > > wmcdonald@DESKTOP-9HGJE25:~$ echo $IN > 2025.07.01 > wmcdonald@DESKTOP-9HGJE25:~$ date -d $IN +%Y%m%d > date: invalid date ‘2025.07.01’ > wmcdonald@DESKTOP-9HGJE25:~$ > > So that step's going to fail. And the while loop can't evaluate the dotted notation strings for greater/less than. The easiest thing to do is strip the dots from the input, then add them back in in the output. This isn't elegant, and someone may provide a better answer but this works: > > #!/bin/bash > start=$1 > end=$2 > > start=$(date -d $(echo $start | sed 's/\./-/g') +%Y%m%d) > end=$(date -d $(echo $end | sed 's/\./-/g') +%Y%m%d) > > date -d"$start" +%Y.%m.%d > > while [[ $start -lt $end ]] > do > date -d"$start + 1 day" +%Y.%m.%d > start=$(date -d"$start + 1 day" +%Y%m%d) > done > > wmcdonald@DESKTOP-9HGJE25:~$ ./daterange.sh 2025.07.01 2025.07.16 > 2025.07.01 > 2025.07.02 > 2025.07.03 > 2025.07.04 > 2025.07.05 > 2025.07.06 > 2025.07.07 > 2025.07.08 > 2025.07.09 > 2025.07.10 > 2025.07.11 > 2025.07.12 > 2025.07.13 > 2025.07.14 > 2025.07.15 > 2025.07.16 > > > Yes Sir. It does the job. It works but it doesn't print four iterations of the date. A for loop inside will do it, but I am not sure how to it? In here, > do > date -d"$start + 1 day" +%Y.%m.%d > start=$(date -d"$start + 1 day" +%Y%m%d) A for i=1..4 and print four versions of each date. But my skills aren't that great. Best Regards, Antonio -- _______________________________________________ users mailing list -- users@xxxxxxxxxxxxxxxxxxxxxxx To unsubscribe send an email to users-leave@xxxxxxxxxxxxxxxxxxxxxxx Fedora Code of Conduct: https://docs.fedoraproject.org/en-US/project/code-of-conduct/ List Guidelines: https://fedoraproject.org/wiki/Mailing_list_guidelines List Archives: https://lists.fedoraproject.org/archives/list/users@xxxxxxxxxxxxxxxxxxxxxxx Do not reply to spam, report it: https://pagure.io/fedora-infrastructure/new_issue
