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On Friday, June 27th, 2025 at 7:18 AM, olivares33561 via users <users@xxxxxxxxxxxxxxxxxxxxxxx> wrote:
>
>
> Sent from ProtonMail, encrypted email based in Switzerland.
>
> Sent with Proton Mail secure email.
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> On Friday, June 27th, 2025 at 7:02 AM, Will McDonald wmcdonald@xxxxxxxxx wrote:
>
> > On Fri, 27 Jun 2025 at 12:32, olivares33561 via users users@xxxxxxxxxxxxxxxxxxxxxxx wrote:
> >
> > > I am struggling to create a script that generates a series of dates with special "+%Y.%m.%d" like the following
> > >
> > > 2025.06.01
> > > 2025.06.01
> > > 2025.06.01
> > >
> > > I found several examples but can't succeed to get what I want
> > > ------
> > >
> > > #!/bin/bash
> > > start=$1
> > > end=$2
> > >
> > > start=$(date -d $start +%Y%m%d)
> > > end=$(date -d $end +%Y%m%d)
> > >
> > > while [[ $start -le $end ]]
> > > do
> > > echo $start
> > > start=$(date -d"$start + 1 day" +"%Y%m%d")
> > > done
> > > ------
> >
> > The date command can't parse dates with periods/dots in this step: start=$(date -d $start +%Y%m%d)
> >
> > Example:
> >
> > wmcdonald@DESKTOP-9HGJE25:~$ echo $IN
> > 2025.07.01
> > wmcdonald@DESKTOP-9HGJE25:~$ date -d $IN +%Y%m%d
> > date: invalid date ‘2025.07.01’
> > wmcdonald@DESKTOP-9HGJE25:~$
> >
> > So that step's going to fail. And the while loop can't evaluate the dotted notation strings for greater/less than. The easiest thing to do is strip the dots from the input, then add them back in in the output. This isn't elegant, and someone may provide a better answer but this works:
> >
> > #!/bin/bash
> > start=$1
> > end=$2
> >
> > start=$(date -d $(echo $start | sed 's/\./-/g') +%Y%m%d)
> > end=$(date -d $(echo $end | sed 's/\./-/g') +%Y%m%d)
> >
> > date -d"$start" +%Y.%m.%d
> >
> > while [[ $start -lt $end ]]
> > do
> > date -d"$start + 1 day" +%Y.%m.%d
> > start=$(date -d"$start + 1 day" +%Y%m%d)
> > done
> >
> > wmcdonald@DESKTOP-9HGJE25:~$ ./daterange.sh 2025.07.01 2025.07.16
> > 2025.07.01
> > 2025.07.02
> > 2025.07.03
> > 2025.07.04
> > 2025.07.05
> > 2025.07.06
> > 2025.07.07
> > 2025.07.08
> > 2025.07.09
> > 2025.07.10
> > 2025.07.11
> > 2025.07.12
> > 2025.07.13
> > 2025.07.14
Dear Will, thanks for your help. I was able to do it.
The following does the job!
------
#!/bin/bash
start=$1
end=$2
start=$(date -d $(echo $start | sed 's/\./-/g') +%Y%m%d)
end=$(date -d $(echo $end | sed 's/\./-/g') +%Y%m%d)
date -d"$start" +%Y.%m.%d
while [[ $start -lt $end ]]
do
for i in {1..4}; do
date -d"$start + 1 day" +%Y.%m.%d
done
start=$(date -d"$start + 1 day" +%Y%m%d)
done
------
Regards,
Antonio
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