script to loop through dates

[olivares33561 via users <users@xxxxxxxxxxxxxxxxxxxxxxx>]

Dear Fedora users,

I am struggling to create a script that generates a series of dates with special "+%Y.%m.%d" like the following 

2025.06.01
2025.06.01
2025.06.01
2025.06.01
2025.06.02
..
..
..
2025.06.03
..
..
..
. 
Through 
2025.06.30

Print four dates of June 1, then June 2, all the way through to June 30

I found several examples but can't succeed to get what I want
------

#!/bin/bash
start=$1
end=$2

start=$(date -d $start +%Y%m%d)
end=$(date -d $end +%Y%m%d)

while [[ $start -le $end ]]
do
    echo $start
    start=$(date -d"$start + 1 day" +"%Y%m%d")
done
------

bash daterange.sh 2025-07-01 2025-07-16
20250701
20250702
20250703
20250704
20250705
20250706
20250707
20250708
20250709
20250710
20250711
20250712
20250713
20250714
20250715
20250716

I found the script here:


https://techieroop.com/loop-through-a-date-range-in-shell-script/


Fix it to print for example above

2025.07.01
2025.07.01
2025.07.01
2025.07.01
2025.07.02
..
..
..
.
.
.
2025.07.16

I have changed date format to %Y.%m.%d but I get errors 

.../Download/mptmp $ bash daterange.sh 2025-07-01 2025-07-16
daterange.sh: line 8: [[: 2025.07.01: syntax error: invalid arithmetic operator (error token is ".07.01")
.../Download/mptmp $ bash daterange.sh 2025.07.01 2025.07.16
date: invalid date ‘2025.07.01’
date: invalid date ‘2025.07.16’

daterange.sh: line 8: [[: 2025.06.27: syntax error: invalid arithmetic operator (error token is ".06.27")


How can it be fixed to do what I want?

Best Regards,


Antonio


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