On 5/10/25 4:41 AM, Patrick O'Callaghan wrote:
On Fri, 2025-05-09 at 23:20 -0700, ToddAndMargo via users wrote:
On 5/9/25 9:06 PM, Dave Close wrote:
Francis.Montagnac@xxxxxxxx wrote:
No: du rounds up:
echo > one
du -m one
1 one
That is correct, not rounded. 'echo' creates a file with one byte,
a newline (0x0a).
Actually, it creates a file that is allocated 4096 bytes.
$ echo > one
$ du -m one
1 one
$ du --block-size=1 one
4096 one
No, the file is allocated 1 byte. The disk usage depends on the
filesystem. IIRC some filesystems could - at least historically - use
spare space in the inode for small files. That's why the output of 'du'
is usually different from that of 'ls -s'. It's the difference between
the *file size* and the *disk usage* (the clue is in the name).
I believe it is called a "cluster", but I may be wrong
on the name.
A cluster is usually regarded as a group of basic allocatable units
(i.e. blocks or pages), so this would not be a cluster except in the
degenerate sense, i.e. a cluster of 1.
poc
Indeed. The file's length is one byte.
The space on the drive allocated for that one byte
file is 4096 bytes.
If the file grows to 4097 bytes, the file will
get allocated another 4096 bytes for 8192 bytes.
And so on and so forth.
--
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