On 9/3/25 13:55, Stefanie Leisestreichler (Febas) wrote:
Hi.
I have the system layout shown below.
To avoid data loss, I want to change HDs which have about 46508 hours of
up time.
I thought, instead of degrading, formatting, rebuilding and so on, I could
- shutdown the computer
- take i.e. /dev/sda and do
- dd bs=98304 conv=sync,noerror if=/dev/sda of=/dev/sdX (X standig for
device name of new disk)
Why would you do that?
In the end, you will have to transfer data from the entire disk
(to a new disk). And that will be the main drag, at it'll take ages.
And there it doesn't matter if you use 'dd' or md resync; both will
be taking roughly the same time.
Is it save to do it this way, presuming the array is in AA-State?
I would not recommend it.
Replacing drives is _precisely_ why RAID was created in the first place,
so really there is no difference between replacing a faulty drive or
replacing a non-faulty drive.
So I would strongly recommend to use MD tools to replace the drive;
it will serve as a nice exercise on what to do in case of a real
fault :-)
Cheers,
Hannes
--
Dr. Hannes Reinecke Kernel Storage Architect
hare@xxxxxxx +49 911 74053 688
SUSE Software Solutions GmbH, Frankenstr. 146, 90461 Nürnberg
HRB 36809 (AG Nürnberg), GF: I. Totev, A. McDonald, W. Knoblich
