Remove a useless comment related to kfifo_init(). The size of the buffer is expected to be a power of 2, as already stated a few liens above. There is no point is speaking of "the number of elements" here. If kfifo_init() is used, then the internal buffer is explicitly allocated using a memory allocation function such a kvalloc() and the needed context is stored in a struct kfifo. In such a case, the "size" of an element is defined a sizeof(unsigned char) which is 1. Signed-off-by: Christophe JAILLET <christophe.jaillet@xxxxxxxxxx> --- include/linux/kfifo.h | 1 - 1 file changed, 1 deletion(-) diff --git a/include/linux/kfifo.h b/include/linux/kfifo.h index 54fbe2ae6fbd..707dd90138d2 100644 --- a/include/linux/kfifo.h +++ b/include/linux/kfifo.h @@ -389,7 +389,6 @@ __kfifo_int_must_check_helper( \ * * This macro initializes a fifo using a preallocated buffer. * - * The number of elements will be rounded-up to a power of 2. * Return 0 if no error, otherwise an error code. */ #define kfifo_init(fifo, buffer, size) \ -- 2.49.0
