Hello, I've come across an issue with `git rev-list --no-walk=sorted` commit ordering when two commits have the exact same commit date. In that case, `git rev-list` will leave the two commits in the original order, preventing automated cherry-picking. To reproduce starting from the attached repo archive created with `git bugreport`: git rev-list --reverse HEAD | git rev-list --no-walk=sorted --stdin You'll see that the order of the two middle commits is incorrect and does not match the order returned by `git rev-list HEAD` Since both commits have the same commit date, `git rev-list` should use another criterion to do the sorting - namely, use the parent/child topology. If there are better ways to sort such a list, let me know. This is a much simplified test case. In our real-world application, we start from a subset of commits that we want to cherry-pick from a branch, for the purpose of creating a customer-specific patch build. For the automated cherry-pick to work, we need to have these commits sorted in topological order. I do not see an option to `git rev-list` that only sorts the commits in stdin topologically - the `--no-walk` option only does date-based sorting. Below is the system info gathered by `git bugreport`. Take care, Clement [System Info] git version: git version 2.48.1 cpu: x86_64 no commit associated with this build sizeof-long: 8 sizeof-size_t: 8 shell-path: /bin/sh libcurl: 7.87.0 OpenSSL: OpenSSL 1.0.1e-fips 11 Feb 2013 zlib: 1.2.3 uname: Linux 4.18.0-553.33.1.el8_10.x86_64 #1 SMP Thu Dec 19 14:28:01 UTC 2024 x86_64 compiler info: gnuc: 6.2 libc info: glibc: 2.28 $SHELL (typically, interactive shell): /bin/zsh [Enabled Hooks]
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